Question: nasıl verileri bir veritabanına yazar bir komut dosyası geçirilir, böylece jQuery ve $. Ajax isteği kullanarak bir form işleyebilir?
Problem: I have a simple email signup form that when processed, adds the email along with the current date to a table in a MySQL database. Processing the form without jQuery works as intended, adding the email and date. With jQuery, the form submits successfully and returns the success message. However, no data is added to the database.
Herhangi bir fikir büyük takdir!
<!-- PROCESS.PHP -->
<?php
// DB info
$dbhost = '#';
$dbuser = '#';
$dbpass = '#';
$dbname = '#';
// Open connection to db
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql');
mysql_select_db($dbname);
// Form variables
$email = $_POST['email'];
$submitted = $_POST['submitted'];
// Clean up
function cleanData($str) {
$str = trim($str);
$str = strip_tags($str);
$str = strtolower($str);
return $str;
}
$email = cleanData($email);
$error = "";
if(isset($submitted)) {
if($email == '') {
$error .= '<p class="error">Please enter your email address.</p>' . "\n";
} else if (!eregi("^[A-Z0-9._%-]+@[A-Z0-9._%-]+\.[A-Z]{2,4}$", $email)) {
$error .= '<p class="error">Please enter a valid email address.</p>' . "\n";
}
if(!$error){
echo '<p id="signup-success-nojs">You have successfully subscribed!</p>';
// Add to database
$add_email = "INSERT INTO subscribers (email,date) VALUES ('$email',CURDATE())";
mysql_query($add_email) or die(mysql_error());
}else{
echo $error;
}
}
?>
<!-- SAMPLE.PHP -->
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Sample</title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
// Email Signup
$("form#newsletter").submit(function() {
var dataStr = $("#newsletter").serialize();
alert(dataStr);
$.ajax({
type: "POST",
url: "process.php",
data: dataStr,
success: function(del){
$('form#newsletter').hide();
$('#signup-success').fadeIn();
}
});
return false;
});
});
</script>
<style type="text/css">
#email {
margin-right:2px;
padding:5px;
width:145px;
border-top:1px solid #ccc;
border-left:1px solid #ccc;
border-right:1px solid #eee;
border-bottom:1px solid #eee;
font-size:14px;
color:#9e9e9e;
}
#signup-success {
margin-bottom:20px;
padding-bottom:10px;
background:url(../img/css/divider-dots.gif) repeat-x 0 100%;
display:none;
}
#signup-success p, #signup-success-nojs {
padding:5px;
background:#fff;
border:1px solid #dedede;
text-align:center;
font-weight:bold;
color:#3d7da5;
}
</style>
</head>
<body>
<?php include('process.php'); ?>
<form id="newsletter" class="divider" name="newsletter" method="post" action="">
<fieldset>
<input id="email" type="text" name="email" />
<input id="submit-button" type="image" src="<?php echo $base_url; ?>/assets/img/css/signup.gif" alt=" SIGNUP " />
<input id="submitted" type="hidden" name="submitted" value="true" />
</fieldset>
</form>
<div id="signup-success"><p>You have successfully subscribed!</p></div>
</body>
</html>
