PHP property_exists ile sorun () olması

2 Cevap php

Hey tüm ... Ben aşağıdaki kodu çalıştırdığınızda, if(property_exists(get_class($puzzleCharacters_encrypted), $solutionCharacter) yanlış değerlendirmek tutar, ancak doğru bilgi gösteriyor ki önceki yankı ifadeler, yani özellikler kesinlikle vardır. Ben eksik olabilir bir şey? (PHP Version 5.2.11)

$puzzle_solution = $currentPuzzleData->getVal("text");
$puzzle_encryption = "";
for ($i = 0; $i < strlen($puzzle_solution); $i++)
{
    $solutionCharacter = substr($puzzle_solution, $i, 1);
    echo ("\$solutionCharacter = " . $solutionCharacter . "<br />\n");
    echo ("\$puzzleCharacters_encrypted->getVal(" . $solutionCharacter . ") = " . $puzzleCharacters_encrypted->getVal($solutionCharacter) . "<br />\n");
    if (property_exists(get_class($puzzleCharacters_encrypted), $solutionCharacter))
    {
        $encryptionCharacter = $puzzleCharacters_encrypted->getVal($solutionCharacter);
        $puzzle_encryption .= $encryptionCharacter;
    }
    else
    {
        $puzzle_encryption .= $solutionCharacter;
    }
}
echo ("<br />\n" . $puzzle_solution);
echo ("<br />\n" . $puzzle_encryption);

Teşekkürler!

2 Cevap

Çünkü kodun bir cevap olarak bu Gönderme ...

class puzzleCharacters
{
    public $char_a;
    public $char_b;
    public $char_c;
    public $char_d;
    public $char_e;
    public $char_f;
    public $char_g;
    public $char_h;
    public $char_i;
    public $char_j;
    public $char_k;
    public $char_l;
    public $char_m;
    public $char_n;
    public $char_o;
    public $char_p;
    public $char_q;
    public $char_r;
    public $char_s;
    public $char_t;
    public $char_u;
    public $char_v;
    public $char_w;
    public $char_x;
    public $char_y;
    public $char_z;
    public $char_A;
    public $char_B;
    public $char_C;
    public $char_D;
    public $char_E;
    public $char_F;
    public $char_G;
    public $char_H;
    public $char_I;
    public $char_J;
    public $char_K;
    public $char_L;
    public $char_M;
    public $char_N;
    public $char_O;
    public $char_P;
    public $char_Q;
    public $char_R;
    public $char_S;
    public $char_T;
    public $char_U;
    public $char_V;
    public $char_W;
    public $char_X;
    public $char_Y;
    public $char_Z;
    public $char_0;
    public $char_1;
    public $char_2;
    public $char_3;
    public $char_4;
    public $char_5;
    public $char_6;
    public $char_7;
    public $char_8;
    public $char_9;

    public function setVal($prop, $val)
    {
        $this->{"char_" . $prop} = $val;
        //echo ("setting \$this->\$char_" . $prop . " as " . $val . "<br />\n");
    }

    public function getVal($prop)
    {
        //echo ("getting \$" . $prop . " as " . $this->{"char_" . $prop} . "<br />\n");
        return ($this->{"char_" . $prop});
    }
}

PrintR çıkış ($ puzzleCharacters_encrypted):

.puzzleCharacters Object ( [char_a] => x [char_b] => i [char_c] => y [char_d] => j [char_e] => o [char_f] => m [char_g] => p [char_h] => n [char_i] => v [char_j] => l [char_k] => w [char_l] => s [char_m] => u [char_n] => e [char_o] => f [char_p] => h [char_q] => q [char_r] => b [char_s] => k [char_t] => z [char_u] => a [char_v] => r [char_w] => t [char_x] => c [char_y] => d [char_z] => g [char_A] => X [char_B] => I [char_C] => Y [char_D] => J [char_E] => O [char_F] => M [char_G] => P [char_H] => N [char_I] => V [char_J] => L [char_K] => W [char_L] => S [char_M] => U [char_N] => E [char_O] => F [char_P] => H [char_Q] => Q [char_R] => B [char_S] => K [char_T] => Z [char_U] => A [char_V] => R [char_W] => T [char_X] => C [char_Y] => D [char_Z] => G [char_0] => 7 [char_1] => 5 [char_2] => 8 [char_3] => 0 [char_4] => 4 [char_5] => 6 [char_6] => 2 [char_7] => 3 [char_8] => 1 [char_9] => 9 )

İkinci echo deyimi aslında $solutionCharacter koymak olduğu bir dize çıktısı, nesne sorgulama değil. Bu özellik aslında var olduğuna dair hiçbir kanıt yoktur.

Ardından, class in $puzzleCharacters_encrypted özellik için sorguluyorsunuz. Bu özellik de sınıfında tanımlanan, ancak nesne değildir olabilir.

Eğer çalışırsanız ne olur

if (property_exists($puzzleCharacters_encrypted, $solutionCharacter))

?

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