$text = preg_replace('/ffc/', 'replacement text',  $subject);

PHP için online kılavuzlarını oldukça şaşırtıcı ve dilleri en iyi özelliklerinden biri:

http://php.net/preg_replace

Sadece bu yüzden gibi str_replace işlevi kullanın:

$text = str_replace('ffc', 'Hello', $text);

preg_replace(); will do.

Explaination:

preg_replace  (  mixed $pattern  ,  mixed $replacement  ,  mixed $subject  [,  int $limit = -1  [,  int &$count  ]] )

The pattern to search for. It can be either a string or an array with

dizeleri.

The e modifier makes preg_replace() treat the replacement

parameter as PHP code after the appropriate references substitution is done. Tip: make sure that replacement constitutes a valid PHP code string, otherwise PHP will complain about a parse error at the line containing preg_replace().

The string or an array with strings to replace. If this parameter is a string and the pattern parameter is an array, all patterns will be replaced by that string. If both pattern and replacement parameters are arrays, each pattern will be replaced by the replacement counterpart. If there are fewer elements in the replacement array than in the pattern array, any extra patterns will be replaced by an empty string.

replacement may contain references of the form \\n or (since PHP 4.0.4)

$n, with the latter form being the preferred one. Every such reference will be replaced by the text captured by the n'th parenthesized pattern. n can be from 0 to 99, and \0 or $0 refers to the text matched by the whole pattern. Opening parentheses are counted from left to right (starting from 1) to obtain the number of the capturing subpattern. To use backslash in replacement, it must be doubled ("\\" PHP string).

When working with a replacement pattern where a backreference is

immediately followed by another number (i.e.: placing a literal number immediately after a matched pattern), you cannot use the familiar \1 notation for your backreference. \11, for example, would confuse preg_replace() since it does not know whether you want the \1 backreference followed by a literal 1, or the \11 backreference followed by nothing. In this case the solution is to use \${1}1. This creates an isolated $1 backreference, leaving the 1 as a literal.

When using the e modifier, this function escapes some characters

(namely ', ", \ and NULL) in the strings that replace the backreferences. This is done to ensure that no syntax errors arise from backreference usage with either single or double quotes (e.g. 'strlen(\'$1\')+strlen("$2")'). Make sure you are aware of PHP's string syntax to know exactly how the interpreted string will look like.

The string or an array with strings to search and replace.

If subject is an array, then the search and replace is performed on

every entry of subject, and the return value is an array as well.

The maximum possible replacements for each pattern in each subject string.

If specified, this variable will be filled with the number of replacements done. Defaults to -1 (no limit).

preg_replace() returns an array if the subject parameter is an array, or a string otherwise.

If matches are found, the new subject will be returned, otherwise subject will be returned unchanged or NULL if an error occurred.

Tam kelimeyi değiştirme gereksinimi giderek, ben şu öneririm:

$text = preg_replace ('/\bffc\b/', 'Hello', $text);

'FFC' tüm örneklerini değiştirir ve harf duyarlıdır