AJAX + PHP + HTML YARDIM: AJAX yenileme sitenin düzenini bozma

0 Cevap php

Ben bu kodu çalıştırdığınızda herkes sayfa kendi kendini tekrarlar, bana burada yardımcı olabilir. Ben de onu yapıyor değil hangi yenilemeniz gerekir.

Like this: alt text

EDITED Code Below:

<?php include 'config.php' ?>
<script language="javascript">
function createRequestObject() {

   var req;

   if(window.XMLHttpRequest){
      // Firefox, Safari, Opera...
      req = new XMLHttpRequest();
   } else if(window.ActiveXObject) {
      // Internet Explorer 5+
      req = new ActiveXObject("Microsoft.XMLHTTP");
   } else {
      // There is an error creating the object,
      // just as an old browser is being used.
     alert("Your Browser Does Not Support This Script - Please Upgrade Your Browser ASAP");
   }

   return req;

}

// Make the XMLHttpRequest object
var http = createRequestObject();

function sendRequest(page) {

   // Open PHP script for requests
   http.open('get', page);
   http.onreadystatechange = handleResponse;
   http.send(null);

}

function handleResponse() {

   if(http.readyState == 4 && http.status == 200){

      // Text returned FROM the PHP script
      var response = http.responseText;

      if(response) {
         // UPDATE ajaxTest content
         document.getElementById("msgstatus").innerHTML = response;
      }

   }

}


function repeatloop()
{
sendRequest('test.php'); // replace "inbox-status.php" with your php page's url
setTimeout("repeatloop()", 10000);
}

var replacementDiv = document.createElement("div");
replacementDiv.innerHTML = response;
document.getElementById("msgstatus").innerHTML = replacementDiv.firstChild.innerHTML;

window.onload=function() {
repeatloop();
}
</script>
<link rel="stylesheet" href="style.css" type="text/css" />
</head><body>

<?php // Collet Latest Posts

$query = "
    SELECT Users.UserID, Wall.Message, Users.Forename, Users.Surname 
    FROM Wall
    INNER JOIN Users ON Wall.UserID = Users.UserID
    ORDER BY Wall.MessageID DESC
    LIMIT 20;";
$result = mysql_query($query) or die('Invalid query: ' . mysql_error());

// Collet Post User
    ?>
    <div id ="container">
        <div id="insideleft">
            <ul>
                <li><a href="index.php">Home</a></li>
                <li><a href="profile.php">Edit Profile</a></li>
                <li><a href="wall.php">Community Wall</a></li>
                <li><a href="logout.php">Logout</a></li>
            </ul>
        </div>
        <div id="insideright">
            <h1>Community Wall</h1>
            <br />
            <div id="postcontainer">
                <form method="post" action="wall.php" name="wallpost" id="wallpost">
                    <input type="text" name="message" id="message" class="message" />
                    <input type="submit" name="messagesub" id="messagesub" value="Post Message" class="post"/><br /><br />
                 </fieldset>
                </form>
            </div>
            <span id="msgstatus">
            <?php while ($row = mysql_fetch_assoc($result)) { ?>
            <div id="messagecontainer">
            <img class="pic" src="dummy.gif">
            <p class="messageposter">
            <?php echo "<b>{$row['Forename']} {$row['Surname']}</b><br />"; ?>
            </p>
            <p class="message">
            <?php echo stripslashes($row['Message']); ?>
            </p>
            </div>
            </span>
<?php
} ?>

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