PHP SQL UPDATE FF ve Chrome'da ama IE'de çalışır?

0 Cevap php

the below code works perfectly in FF and CHROME but not in IE. Please help. I have commented out my santize functions as i thought they might be affecting it, but it still does the same.... nothing in IE. Thank you in advance for any assistance.

<?php 

//IF UPDATE BUCKET CHANGE STATUS...
if(isset($_POST['updatebucket'])){


 $complete = $_POST["complete"];
 $bucketid = $_POST["bucketid"];

//$complete = sanitizeone($_POST["complete"], "plain");
//$complete = strip_word_html($complete);
//$bucketid = sanitizeone($_POST["bucketid"], "plain");
//$bucketid = strip_word_html($bucketid);

if ($complete=="1")
  $complete = "0";
else
  $complete = "1";

$updatebucket = "UPDATE membersbuckets SET complete = '$complete' WHERE userid = '$userid' AND bucketid = '$bucketid'"; 
mysql_query($updatebucket);
}
?>

ve ön uç ....

<? if ($complete=="1") {
    echo "<form action='' method='post' name='updatebucket'><input name='complete' type='hidden' value=" .$complete. " /><input name='userid' type='hidden' value=" .$userid. " /><input name='bucketid' type='hidden' value=" .$bucketid. " /><input type='image' name='updatebucket' value='updatebucket' src='images/tick.png' /></form>";
    }else{
    echo "<form action='' method='post' name='updatebucket'><input name='complete' type='hidden' value=" .$complete. " /><input name='userid' type='hidden' value=" .$userid. " /><input name='bucketid' type='hidden' value=" .$bucketid. " /><input type='image' name='updatebucket' value='updatebucket' src='images/cross.png' /></form>";  
}
?>

Dan

0 Cevap