I'm running a query to update a small group of 'items' in a table, from PHP. Running the code with "Sequel Pro" executes it perfectly, while running it on PHP using mysql("query here"); fails miserably.
Benim sorgu ile yanlış bir şey var mı?
UPDATE `service_joblocation`
SET `in_use` = '1',
`in_use_since` = '1283488686',
`in_use_currentcount` = `in_use_currentcount`+1,
`in_use_historicalcount`= `in_use_historicalcount`+1
WHERE `id` = 5
LIMIT 1;
UPDATE `service_joblocation`
SET `in_use` = '1',
`in_use_since` = '1283488686',
`in_use_currentcount` = `in_use_currentcount`+1,
`in_use_historicalcount` = `in_use_historicalcount`+1
WHERE `id`=16
LIMIT 1;
UPDATE `service_joblocation`
SET `in_use` = '1',
`in_use_since` = '1283488686',
`in_use_currentcount` = `in_use_currentcount`+1,
`in_use_historicalcount` = `in_use_historicalcount`+1
WHERE `id`=18
LIMIT 1;
UPDATE `service_items` SET `checkin_user`='9', `checkin_date`='1283488686', `location`='5' WHERE `id`=576;
UPDATE `service_items` SET `checkin_user`='9', `checkin_date`='1283488686', `location`='16' WHERE `id`=577;
UPDATE `service_items` SET `checkin_user`='9', `checkin_date`='1283488686', `location`='18' WHERE `id`=578;
UPDATE `service_jobs` SET `checkin_date`='1283488686', `checkin_user`='9',`checkin_department`='1',`checkin_client_person`='0', `items_x`=`items_x`+1 WHERE `id`='518' LIMIT 1;
UPDATE `service_jobs` SET `checkin_date`='1283488686', `checkin_user`='9',`checkin_department`='1',`checkin_client_person`='0', `items_x`=`items_x`+1 WHERE `id`='518' LIMIT 1;
UPDATE `service_jobs` SET `checkin_date`='1283488686', `checkin_user`='9',`checkin_department`='1',`checkin_client_person`='0', `items_x`=`items_x`+1 WHERE `id`='518' LIMIT 1;
Bu çıkış mesajı ...
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'UPDATE
service_joblocation
SETin_use
= '1',in_use_since
= '1283488686' at line 2