i dosya 1.html var:

.....


 <script src="/libs/jquery-1.3.1.min.js" type="text/javascript"></script>
    <script type="text/javascript">
    var url0='{$url0}';
    var url1='{$url1}';
    var url2='{$url2}';
    var url3='{$url3}';
    var OPEN_ON = false;
    openurls= function(){
    if(confirm('Opens all?') && OPEN_ON == false){
                    OPEN_ON = true;
    $.ajax({<br/>
        type: "POST",
        url: "a1.php",
        data: jsonData,
        contentType: "application/json; charset=utf-8",
        dataType: "json",
        success: function(msg) {
            success = true;

        },
        error: function(msg) {

        }
    })

    if(success) { 
     window.open(url0)
     window.open(url1)
    window.open(url2)
    window.open(url3) 
    }


                 setTimeout("location.reload(true);",3000) 

                    OPEN_ON = false
                }
                return false

    }

Question is:
How do I send url0, url1, url2 and url3 to the file a1.php and there after checking some conditions to send them back.enter code here