Konsol bu çalışmıyor neden .. bazı rehberlik takdir gibi bu yüzden bir kayıp değilim, Firebug ne herhangi bir hataları gösteren değil!

Benim formu:

    <form action="" method="post" id="sendEmail">
    <div class="alignleft">
        <p><label for="order_ref">Photo ID:</label><input type="text" name="order_ref" id="order_ref" class="text smallinput" disabled="disabled" value="<? echo $ref; ?>"/></p>
        <p><label for="order_name">Full Name:</label><input type="text" name="order_name" id="order_name" class="text" tabindex="10" /></p>
        <p><label for="order_telephone">Contact Number:</label><input type="text" name="order_telephone" id="order_telephone" class="text" tabindex="20" /></p>
        <p><label for="order_email">Email Address:</label><input type="text" name="order_email" id="order_email" class="text" tabindex="30" /></p>
    </div>

    <div class="alignright">
        <p class="higher"><label for="order_message">Message</label><textarea name="order_message" id="order_message" class="uniform" tabindex="40"></textarea></p>
    </div>

    <div class="rounded color_grey"><p>Clicking confirm will mail your order to us. We'll be in touch shortly. <input type="submit" id="submit" name="submit" value="" class="alignright" /></p></div>
</form>

Sonra benim JS:

    // JavaScript Document

var g = jQuery.noConflict();

g(document).ready( function() {

    g("#submit").click(function(){                                     

        // set initial error value to false
        var hasError = false;

        // set var for each form field
        var order_ref = g("#order_ref").val();
        var order_name = g("#order_name").val();
        var order_telephone = g("#order_telephone").val();
        var order_email = g("#order_email").val();
        var order_message = g("#order_message").val();

        // validate each of them
        if(order_ref == '') { g("#order_ref").addClass('haserror'); hasError = true; } 
        if(order_name == '') { g("#order_name").addClass('haserror'); hasError = true; } 
        if(order_telephone == '') {  g("#order_telephone").addClass('haserror'); hasError = true; } 
        if(order_email == '') { g("#order_email").val().addClass('haserror'); hasError = true; } 
        if(order_message == '') { g("#order_message").val().addClass('haserror'); hasError = true; } 


        // if there's no errors, proceed            
        if(hasError == false) {
            //alert('no errors');
            g.post("/photo/theme/foodphoto/includes/mail_send.php",
                { 
                    // pass each of the form values to the PHP file for processing
                    order_ref: order_ref, 
                    order_name: order_name, 
                    order_telephone: order_telephone, 
                    order_email: order_email, 
                    order_message: order_message
                },
                    function(data){
                        // no errors? great now do what you want to show the user his message is sent
                        alert('sent');
                    }
                 );
        }

        return false;
    }); 

});

Ve PHP (mail_send.php) göndermek gerektiğini

<pre><?php

// receive & save each of the vars from the AJAX request
$order_ref = $_POST['order_ref'];
$order_name = $_POST['order_name'];
$order_telephone = $_POST['order_telephone'];
$order_email = $_POST['order_email'];
$order_message = $_POST['order_message'];

// setup the email requirements 
$to = "email@address.com";
$subject = "Order Has Been Placed";

// what must be in the mail message
$message = "The following order has been placed on your website:";

$headers  = 'MIME-Version: 1.0' . "\r\n";
$headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n";
$headers .= 'From: '.$order_name.' <'.$order_email.'>';

mail($to, $subject, $message, $headers);

>

Konsolu PHP sorunları raporlar ve Kundakçı (ben bu kullanarak yeni am, bu yüzden bir şey atlanır olabilir?) Hiçbir sorunları raporları ...?

Ben yanlış ne yapıyorum?

Çok teşekkürler!