Ben Ajax tarafından erişilen bir sayfada bir formu göndermek için nasıl anlamaya çalışıyorum?
Burada i söylemeye çalışıyorum ne göstermek için bazı kod parçacıkları vardır.
HTML BODY - THIS IS WHAT THE USER WILL SEE.
<html>
<head>
<script language="javascript" src="linktoajaxfile.js">
</head>
<body onLoad="gotoPage(0)">
<div id="fillThis">
</div>
</body>
</html>
AJAX FILE
var xmlhttp
function gotoPage(phase)
{
xmlhttp=GetXmlHttpObject();
if (xmlhttp==null)
{
alert ("Your browser does not support AJAX!");
return;
}
var url="pageofstuffce.php";
url=url+"?stg="+phase;
url=url+"&sid="+Math.random();
xmlhttp.onreadystatechange=stateChanged;
xmlhttp.open("GET",url,true);
xmlhttp.send(null);
}
function stateChanged()
{
if (xmlhttp.readyState==4)
{
document.getElementById("fillThis").innerHTML=xmlhttp.responseText;
}
}
function GetXmlHttpObject()
{
if (window.XMLHttpRequest)
{
// code for IE7+, Firefox, Chrome, Opera, Safari
return new XMLHttpRequest();
}
if (window.ActiveXObject)
{
// code for IE6, IE5
return new ActiveXObject("Microsoft.XMLHTTP");
}
return null;
}
PAGE OF DATA
<?php
$stage = $_GET['stg'];
if($stage == 0)
{
echo '<a onClick="gotoPage(1)">click me</a>';
}
elseif($stage == 1)
{
<form>
<input type="text" name="name">
<input type="submit" name="submit">
</form>
}
elseif(somehow can reach here)
{
show data from form.
}
?>
Can anyone perhaps help me get past the form and display the data in the same page? Also, i have looked around, and i don't think anything around has what i need... correct me if i'm wrong though :)
Thanks in advance, and i hope i didn't put in too much detail :) Dronnoc
EDIT
Forgot to mention what I've tried; I have tried submitting the form to itself (same file) and that destroyed the ajax link, and opened the page. i have also tried just having the button move the page onto another step, but the $_POST variable is empty... i am at a loss, so does anyone else have any ideas?