php json boş hatası yardım

0 Cevap php

Ben hata olarak 'json null' olsun

Benim php dosyası:

<?php


    if (isset($_REQUEST['query'])) {  
    $query = $_REQUEST['query'];
    $url='https://www.googleapis.com/urlshortener/v1/';
$key='ApiKey';
$result= $url.($query).$key;
$ch = curl_init($result);
curl_setopt($ch, CURLOPT_HEADER, 0); 
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,1);
$resp = curl_exec($ch);
curl_close($ch); 
echo $resp;
    }
?>

Benim html:

<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
    // when the user clicks the button
    $("button").click(function(){

          $.getJSON("shortner.php?query="+$('#query').attr("value"),function(json){

             $('#results').append('<p>Id : ' + json.id+ '</p>');
             $('#results').append('<p>Longurl: ' + json.longurl+ '</p>');



});


    });
});


</script>

</head>
<body>

<input type="text" value="Enter a place" id="query" /><button>Get Coordinates</button>
<div id="results"></div>

Düzenlendi:

<?php


    if (isset($_REQUEST['query'])) {  
    $query = $_REQUEST['query'];
    $url='https://www.googleapis.com/urlshortener/v1/';
$key='Api';
$key2='?key=';

$result= $url.$query.$key2.$key;
$requestData= json_encode($result);
echo var_dump($query);
$ch = curl_init($requestData);
curl_setopt($ch, CURLOPT_HEADER, 0); 
curl_setopt($ch, CURLOPT_POST, 1);

curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,1);
$resp = curl_exec($ch);
curl_close($ch); 
echo $resp;
    }
?>

0 Cevap

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