Ben gibi db-tablodan kullanıcı kaydını getiriliyor am

<?php $row=1; ?>
<select id="status<?php echo $row; ?>" name="status<?php echo $row; ?>">
    <option value="0">Active</option>
    <option value="1">Block</option>
</select>
<?php $row++; ?>

----------------------------------------
  Name                    Status
----------------------------------------
  Abc                     Active
  Def                     Block
  Ghi                     Active
  Jkl                     Block
----------------------------------------

where status is drop-down with two status for each user and If I want to change the status of any user then I select an option from that drop-down and at the same time the status must update in db-table. For this I coded:

for(var r=1; r<=4; r++){
    $("status").each(function() {
        var sld = $("#status").val();
        alert(sld);
        $.ajax({
            type: "POST",
            url: "response.php",
            data: "sld="+sld,
            success: function(msg){
                alert(msg); // this is the response
            }
        });
    });
}

ancak döngü her Açılır için komut dosyası oluşturmak değil ....